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200023133973041 is a prime number
BaseRepresentation
bin101101011110101110000011…
…110110001110101000110001
3222020020000200010021122121202
4231132232003312032220301
5202204134334244114131
61545225205330500545
760063123503663201
oct5536560366165061
9866200603248552
10200023133973041
1158808375598735
121a5259a6a34755
13877c140028022
143757258228401
15181d0da014bcb
hexb5eb83d8ea31

200023133973041 has 2 divisors, whose sum is σ = 200023133973042. Its totient is φ = 200023133973040.

The previous prime is 200023133973017. The next prime is 200023133973043. The reversal of 200023133973041 is 140379331320002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 156437456190016 + 43585677783025 = 12507496^2 + 6601945^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200023133973041 is a prime.

Together with 200023133973043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 200023133972986 and 200023133973004.

It is not a weakly prime, because it can be changed into another prime (200023133973043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100011566986520 + 100011566986521.

It is an arithmetic number, because the mean of its divisors is an integer number (100011566986521).

Almost surely, 2200023133973041 is an apocalyptic number.

It is an amenable number.

200023133973041 is a deficient number, since it is larger than the sum of its proper divisors (1).

200023133973041 is an equidigital number, since it uses as much as digits as its factorization.

200023133973041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 38.

The spelling of 200023133973041 in words is "two hundred trillion, twenty-three billion, one hundred thirty-three million, nine hundred seventy-three thousand, forty-one".