Base | Representation |
---|---|
bin | 111011101000110… |
… | …0101111011011111 |
3 | 12011110102102211202 |
4 | 1313101211323133 |
5 | 13044240204021 |
6 | 530322310115 |
7 | 100406034164 |
oct | 16721457337 |
9 | 5143372752 |
10 | 2001100511 |
11 | 937629483 |
12 | 47a1b833b |
13 | 25b771257 |
14 | 14daa406b |
15 | baa2da0b |
hex | 77465edf |
2001100511 has 2 divisors, whose sum is σ = 2001100512. Its totient is φ = 2001100510.
The previous prime is 2001100483. The next prime is 2001100513. The reversal of 2001100511 is 1150011002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001100511 is a prime.
It is a super-2 number, since 2×20011005112 = 8008806510248922242, which contains 22 as substring.
Together with 2001100513, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001100492 and 2001100501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001100513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000550255 + 1000550256.
It is an arithmetic number, because the mean of its divisors is an integer number (1000550256).
Almost surely, 22001100511 is an apocalyptic number.
2001100511 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001100511 is an equidigital number, since it uses as much as digits as its factorization.
2001100511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10, while the sum is 11.
The square root of 2001100511 is about 44733.6619448934. The cubic root of 2001100511 is about 1260.1521003502.
Adding to 2001100511 its reverse (1150011002), we get a palindrome (3151111513).
The spelling of 2001100511 in words is "two billion, one million, one hundred thousand, five hundred eleven".
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