Base | Representation |
---|---|
bin | 11101000111101011100… |
… | …100110111010011011111 |
3 | 21002022012221110111021011 |
4 | 131013223210313103133 |
5 | 230241234144231421 |
6 | 4131144225120051 |
7 | 264401265134203 |
oct | 35075344672337 |
9 | 7068187414234 |
10 | 2001112102111 |
11 | 701737681641 |
12 | 2839b4489027 |
13 | 11691ca91665 |
14 | 6cbd645cb03 |
15 | 370c09544e1 |
hex | 1d1eb9374df |
2001112102111 has 2 divisors, whose sum is σ = 2001112102112. Its totient is φ = 2001112102110.
The previous prime is 2001112102109. The next prime is 2001112102117. The reversal of 2001112102111 is 1112012111002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001112102111 - 21 = 2001112102109 is a prime.
Together with 2001112102109, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 2001112102091 and 2001112102100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001112102117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000556051055 + 1000556051056.
It is an arithmetic number, because the mean of its divisors is an integer number (1000556051056).
Almost surely, 22001112102111 is an apocalyptic number.
2001112102111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001112102111 is an equidigital number, since it uses as much as digits as its factorization.
2001112102111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 2001112102111 its reverse (1112012111002), we get a palindrome (3113124213113).
The spelling of 2001112102111 in words is "two trillion, one billion, one hundred twelve million, one hundred two thousand, one hundred eleven".
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