Base | Representation |
---|---|
bin | 101101100000000001000001… |
… | …111010011101111001011011 |
3 | 222020112112121211022110120121 |
4 | 231200001001322131321123 |
5 | 202212114312324213313 |
6 | 1545334141414334111 |
7 | 60102426261404005 |
oct | 5540010172357133 |
9 | 866475554273517 |
10 | 200112222101083 |
11 | 58842131508936 |
12 | 1a53b10a35a337 |
13 | 8787669c57ca6 |
14 | 375b6a9d99375 |
15 | 18205a12bc28d |
hex | b60041e9de5b |
200112222101083 has 2 divisors, whose sum is σ = 200112222101084. Its totient is φ = 200112222101082.
The previous prime is 200112222101081. The next prime is 200112222101147. The reversal of 200112222101083 is 380101222211002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200112222101083 - 21 = 200112222101081 is a prime.
Together with 200112222101081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (200112222101081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056111050541 + 100056111050542.
It is an arithmetic number, because the mean of its divisors is an integer number (100056111050542).
Almost surely, 2200112222101083 is an apocalyptic number.
200112222101083 is a deficient number, since it is larger than the sum of its proper divisors (1).
200112222101083 is an equidigital number, since it uses as much as digits as its factorization.
200112222101083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 200112222101083 its reverse (380101222211002), we get a palindrome (580213444312085).
The spelling of 200112222101083 in words is "two hundred trillion, one hundred twelve billion, two hundred twenty-two million, one hundred one thousand, eighty-three".
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