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2001333222149 is a prime number
BaseRepresentation
bin11101000111111000110…
…000010111101100000101
321002022210100112112221012
4131013320300113230011
5230242212301102044
64131222204332005
7264406621464062
oct35077060275405
97068710475835
102001333222149
1170184047a378
12283a56544005
13116956831b11
146cc1797bc69
15370d508159e
hex1d1f8c17b05

2001333222149 has 2 divisors, whose sum is σ = 2001333222150. Its totient is φ = 2001333222148.

The previous prime is 2001333222089. The next prime is 2001333222181. The reversal of 2001333222149 is 9412223331002.

It is an a-pointer prime, because the next prime (2001333222181) can be obtained adding 2001333222149 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1437737689249 + 563595532900 = 1199057^2 + 750730^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2001333222149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001333222949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000666611074 + 1000666611075.

It is an arithmetic number, because the mean of its divisors is an integer number (1000666611075).

Almost surely, 22001333222149 is an apocalyptic number.

It is an amenable number.

2001333222149 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001333222149 is an equidigital number, since it uses as much as digits as its factorization.

2001333222149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 2001333222149 in words is "two trillion, one billion, three hundred thirty-three million, two hundred twenty-two thousand, one hundred forty-nine".