Base | Representation |
---|---|
bin | 1001000110011110010101… |
… | …01011110101100101111000 |
3 | 2121212021201220012221020201 |
4 | 10203033022223311211320 |
5 | 10110400430144341100 |
6 | 110322051215531544 |
7 | 4133636660443351 |
oct | 443171253654570 |
9 | 77767656187221 |
10 | 20013653121400 |
11 | 6416819483244 |
12 | 22b2943b29bb4 |
13 | b22382a903b3 |
14 | 4d294763ad28 |
15 | 24a9037ea36a |
hex | 1233caaf5978 |
20013653121400 has 96 divisors (see below), whose sum is σ = 47636189593200. Its totient is φ = 7817620608000.
The previous prime is 20013653121379. The next prime is 20013653121437. The reversal of 20013653121400 is 412135631002.
It is a super-2 number, since 2×200136531214002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5311530 + ... + 8260729.
Almost surely, 220013653121400 is an apocalyptic number.
20013653121400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
20013653121400 is an abundant number, since it is smaller than the sum of its proper divisors (27622536471800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20013653121400 is a wasteful number, since it uses less digits than its factorization.
20013653121400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13572449 (or 13572440 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 20013653121400 its reverse (412135631002), we get a palindrome (20425788752402).
The spelling of 20013653121400 in words is "twenty trillion, thirteen billion, six hundred fifty-three million, one hundred twenty-one thousand, four hundred".
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