Base | Representation |
---|---|
bin | 101101100001011101000001… |
… | …100110000101001010100111 |
3 | 222020212222120220020200111202 |
4 | 231201131001212011022213 |
5 | 202220224112224122321 |
6 | 1545451355241153115 |
7 | 60112524150260534 |
oct | 5541350146051247 |
9 | 866788526220452 |
10 | 200211001004711 |
11 | 58880010639184 |
12 | 1a55629718b79b |
13 | 8793a7c797aa8 |
14 | 376239ab97d8b |
15 | 1822e3320070b |
hex | b617419852a7 |
200211001004711 has 2 divisors, whose sum is σ = 200211001004712. Its totient is φ = 200211001004710.
The previous prime is 200211001004617. The next prime is 200211001004713. The reversal of 200211001004711 is 117400100112002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200211001004711 - 210 = 200211001003687 is a prime.
Together with 200211001004713, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200211001004713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105500502355 + 100105500502356.
It is an arithmetic number, because the mean of its divisors is an integer number (100105500502356).
Almost surely, 2200211001004711 is an apocalyptic number.
200211001004711 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211001004711 is an equidigital number, since it uses as much as digits as its factorization.
200211001004711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 200211001004711 its reverse (117400100112002), we get a palindrome (317611101116713).
The spelling of 200211001004711 in words is "two hundred trillion, two hundred eleven billion, one million, four thousand, seven hundred eleven".
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