Base | Representation |
---|---|
bin | 11101001000101001100… |
… | …111100101100110011111 |
3 | 21002101220111002202102121 |
4 | 131020221213211212133 |
5 | 230300402132102143 |
6 | 4131435411203411 |
7 | 264436134505666 |
oct | 35105147454637 |
9 | 7071814082377 |
10 | 2002153003423 |
11 | 7021211a1161 |
12 | 284044ba6567 |
13 | 116a5761c6b1 |
14 | 6cc947b5ddd |
15 | 371320147ed |
hex | 1d2299e599f |
2002153003423 has 2 divisors, whose sum is σ = 2002153003424. Its totient is φ = 2002153003422.
The previous prime is 2002153003421. The next prime is 2002153003481. The reversal of 2002153003423 is 3243003512002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002153003423 - 21 = 2002153003421 is a prime.
Together with 2002153003421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002153003421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001076501711 + 1001076501712.
It is an arithmetic number, because the mean of its divisors is an integer number (1001076501712).
Almost surely, 22002153003423 is an apocalyptic number.
2002153003423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002153003423 is an equidigital number, since it uses as much as digits as its factorization.
2002153003423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 2002153003423 its reverse (3243003512002), we get a palindrome (5245156515425).
The spelling of 2002153003423 in words is "two trillion, two billion, one hundred fifty-three million, three thousand, four hundred twenty-three".
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