Base | Representation |
---|---|
bin | 1001000110101110010000… |
… | …01100010000001101011111 |
3 | 2121220002210121222102210121 |
4 | 10203113020030100031133 |
5 | 10111020432003100413 |
6 | 110330023335215411 |
7 | 4134361545214402 |
oct | 443271014201537 |
9 | 77802717872717 |
10 | 20022201221983 |
11 | 641a405680784 |
12 | 22b452a817567 |
13 | b23115a2a28c |
14 | 4d3118a1bd39 |
15 | 24ac53eb0b8d |
hex | 1235c831035f |
20022201221983 has 2 divisors, whose sum is σ = 20022201221984. Its totient is φ = 20022201221982.
The previous prime is 20022201221977. The next prime is 20022201222017. The reversal of 20022201221983 is 38912210222002.
It is an a-pointer prime, because the next prime (20022201222017) can be obtained adding 20022201221983 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20022201221983 - 241 = 17823177966431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20022201221923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011100610991 + 10011100610992.
It is an arithmetic number, because the mean of its divisors is an integer number (10011100610992).
Almost surely, 220022201221983 is an apocalyptic number.
20022201221983 is a deficient number, since it is larger than the sum of its proper divisors (1).
20022201221983 is an equidigital number, since it uses as much as digits as its factorization.
20022201221983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 34.
Adding to 20022201221983 its reverse (38912210222002), we get a palindrome (58934411443985).
The spelling of 20022201221983 in words is "twenty trillion, twenty-two billion, two hundred one million, two hundred twenty-one thousand, nine hundred eighty-three".
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