Base | Representation |
---|---|
bin | 101101100001100111011101… |
… | …110101000011101100000111 |
3 | 222020221001112012220220021201 |
4 | 231201213131311003230013 |
5 | 202220420042300023421 |
6 | 1545500451530123331 |
7 | 60113402032146121 |
oct | 5541473565035407 |
9 | 866831465826251 |
10 | 200222212111111 |
11 | 58884843a55373 |
12 | 1a5584a5880547 |
13 | 8794b48367a68 |
14 | 3762b41adc211 |
15 | 182338c58eb91 |
hex | b619ddd43b07 |
200222212111111 has 2 divisors, whose sum is σ = 200222212111112. Its totient is φ = 200222212111110.
The previous prime is 200222212111001. The next prime is 200222212111139. The reversal of 200222212111111 is 111111212222002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200222212111111 - 225 = 200222178556679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200222212118111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100111106055555 + 100111106055556.
It is an arithmetic number, because the mean of its divisors is an integer number (100111106055556).
Almost surely, 2200222212111111 is an apocalyptic number.
200222212111111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200222212111111 is an equidigital number, since it uses as much as digits as its factorization.
200222212111111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 200222212111111 its reverse (111111212222002), we get a palindrome (311333424333113).
The spelling of 200222212111111 in words is "two hundred trillion, two hundred twenty-two billion, two hundred twelve million, one hundred eleven thousand, one hundred eleven".
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