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20031001312 = 25789424113
BaseRepresentation
bin10010101001111100…
…001101001011100000
31220200222212022001111
4102221330031023200
5312010414020222
613111353513104
71306246462510
oct225174151340
956628768044
1020031001312
118549a83843
123a70412794
131b72c405ca
14d80475840
157c3841777
hex4a9f0d2e0

20031001312 has 24 divisors (see below), whose sum is σ = 45069753456. Its totient is φ = 8584714752.

The previous prime is 20031001303. The next prime is 20031001327. The reversal of 20031001312 is 21310013002.

It is a super-2 number, since 2×200310013122 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20031001292 and 20031001301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44711833 + ... + 44712280.

It is an arithmetic number, because the mean of its divisors is an integer number (1877906394).

Almost surely, 220031001312 is an apocalyptic number.

It is an amenable number.

20031001312 is an abundant number, since it is smaller than the sum of its proper divisors (25038752144).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20031001312 is an equidigital number, since it uses as much as digits as its factorization.

20031001312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89424130 (or 89424122 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 20031001312 its reverse (21310013002), we get a palindrome (41341014314).

The spelling of 20031001312 in words is "twenty billion, thirty-one million, one thousand, three hundred twelve".

Divisors: 1 2 4 7 8 14 16 28 32 56 112 224 89424113 178848226 357696452 625968791 715392904 1251937582 1430785808 2503875164 2861571616 5007750328 10015500656 20031001312