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2003131120122 = 233114321823837
BaseRepresentation
bin11101001001100011111…
…010110011100111111010
321002111102122121020022000
4131021203322303213322
5230304403031320442
64132120431441430
7264502312405116
oct35114372634772
97074378536260
102003131120122
11702583328770
12284278686276
13116b82167182
146cd48668746
153718cd21d4c
hex1d263eb39fa

2003131120122 has 96 divisors (see below), whose sum is σ = 4971636480960. Its totient is φ = 592892606880.

The previous prime is 2003131120121. The next prime is 2003131120157. The reversal of 2003131120122 is 2210211313002.

2003131120122 is a `hidden beast` number, since 200 + 31 + 311 + 2 + 0 + 122 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 2003131120095 and 2003131120104.

It is not an unprimeable number, because it can be changed into a prime (2003131120121) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 186388 + ... + 2010224.

It is an arithmetic number, because the mean of its divisors is an integer number (51787880010).

Almost surely, 22003131120122 is an apocalyptic number.

2003131120122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 2003131120122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2485818240480).

2003131120122 is an abundant number, since it is smaller than the sum of its proper divisors (2968505360838).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2003131120122 is a wasteful number, since it uses less digits than its factorization.

2003131120122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1823945 (or 1823896 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 2003131120122 its reverse (2210211313002), we get a palindrome (4213342433124).

The spelling of 2003131120122 in words is "two trillion, three billion, one hundred thirty-one million, one hundred twenty thousand, one hundred twenty-two".

Divisors: 1 2 3 6 9 11 18 22 27 33 43 54 66 86 99 129 198 258 297 387 473 594 774 946 1161 1419 1849 2322 2838 3698 4257 5547 8514 11094 12771 16641 20339 25542 33282 40678 49923 61017 99846 122034 183051 366102 549153 1098306 1823837 3647674 5471511 10943022 16414533 20062207 32829066 40124414 49243599 60186621 78424991 98487198 120373242 156849982 180559863 235274973 361119726 470549946 541679589 705824919 862674901 1083359178 1411649838 1725349802 2117474757 2588024703 3372274613 4234949514 5176049406 6744549226 7764074109 10116823839 15528148218 20233647678 23292222327 30350471517 37095020743 46584444654 60700943034 74190041486 91051414551 111285062229 182102829102 222570124458 333855186687 667710373374 1001565560061 2003131120122