200351661113142 has 96 divisors (see below), whose sum is σ = 541285391821824. Its totient is φ = 52032112704000.

The previous prime is 200351661113063. The next prime is 200351661113143. The reversal of 200351661113142 is 241311166153002.

200351661113142 is a `hidden beast` number, since 2 + 0 + 0 + 3 + 5 + 1 + 6 + 611 + 1 + 31 + 4 + 2 = 666.

200351661113142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×200351661113142³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 200351661113097 and 200351661113106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200351661113143) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 195963 + ... + 20018534.

It is an arithmetic number, because the mean of its divisors is an integer number (5638389498144).

Almost surely, 2^{200351661113142} is an apocalyptic number.

200351661113142 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

200351661113142 is an abundant number, since it is smaller than the sum of its proper divisors (340933730708682).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200351661113142 is a wasteful number, since it uses less digits than its factorization.

200351661113142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20221674 (or 20221671 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 36.

The spelling of 200351661113142 in words is "two hundred trillion, three hundred fifty-one billion, six hundred sixty-one million, one hundred thirteen thousand, one hundred forty-two".