200365613141 has 2 divisors, whose sum is σ = 200365613142. Its totient is φ = 200365613140.

The previous prime is 200365613101. The next prime is 200365613143. The reversal of 200365613141 is 141316563002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200229400900 + 136212241 = 447470^2 + 11671^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200365613141 is a prime.

Together with 200365613143, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 200365613098 and 200365613107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200365613143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100182806570 + 100182806571.

It is an arithmetic number, because the mean of its divisors is an integer number (100182806571).

Almost surely, 2^200365613141 is an apocalyptic number.

It is an amenable number.

200365613141 is a deficient number, since it is larger than the sum of its proper divisors (1).

200365613141 is an equidigital number, since it uses as much as digits as its factorization.

200365613141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 32.

The spelling of 200365613141 in words is "two hundred billion, three hundred sixty-five million, six hundred thirteen thousand, one hundred forty-one".