Base | Representation |
---|---|
bin | 1001000111010000010111… |
… | …01010111111110111011111 |
3 | 2121221212001211020112100102 |
4 | 10203220023222333313133 |
5 | 10111320432341133114 |
6 | 110342252405051315 |
7 | 4135610412525011 |
oct | 443501352776737 |
9 | 77855054215312 |
10 | 20040513224159 |
11 | 6427152294a7a |
12 | 22b7b9b3b6b3b |
13 | b24a7379b61c |
14 | 4d3d74a641b1 |
15 | 24b4769492de |
hex | 123a0babfddf |
20040513224159 has 2 divisors, whose sum is σ = 20040513224160. Its totient is φ = 20040513224158.
The previous prime is 20040513224141. The next prime is 20040513224161. The reversal of 20040513224159 is 95142231504002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20040513224159 - 220 = 20040512175583 is a prime.
Together with 20040513224161, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20040513224059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10020256612079 + 10020256612080.
It is an arithmetic number, because the mean of its divisors is an integer number (10020256612080).
Almost surely, 220040513224159 is an apocalyptic number.
20040513224159 is a deficient number, since it is larger than the sum of its proper divisors (1).
20040513224159 is an equidigital number, since it uses as much as digits as its factorization.
20040513224159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 20040513224159 in words is "twenty trillion, forty billion, five hundred thirteen million, two hundred twenty-four thousand, one hundred fifty-nine".
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