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200411310023000 = 2353200411310023
BaseRepresentation
bin101101100100010111100100…
…111100010110000101011000
3222021121010121210000010101222
4231210113210330112011120
5202232014330331214000
61550123403530431212
760133145042654516
oct5544274474260530
9867533553003358
10200411310023000
1158947a6088339a
121a58907a292508
1387a9922b2180b
14376bd5dd194b6
151828258865a85
hexb645e4f16158

200411310023000 has 32 divisors (see below), whose sum is σ = 468962465456160. Its totient is φ = 80164524008800.

The previous prime is 200411310022997. The next prime is 200411310023027. The reversal of 200411310023000 is 320013114002.

200411310023000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×2004113100230003 (a number of 44 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 200411310023000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100205654012 + ... + 100205656011.

It is an arithmetic number, because the mean of its divisors is an integer number (14655077045505).

Almost surely, 2200411310023000 is an apocalyptic number.

200411310023000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

200411310023000 is an abundant number, since it is smaller than the sum of its proper divisors (268551155433160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200411310023000 is a wasteful number, since it uses less digits than its factorization.

200411310023000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200411310044 (or 200411310030 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 200411310023000 its reverse (320013114002), we get a palindrome (200731323137002).

The spelling of 200411310023000 in words is "two hundred trillion, four hundred eleven billion, three hundred ten million, twenty-three thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000 200411310023 400822620046 801645240092 1002056550115 1603290480184 2004113100230 4008226200460 5010282750575 8016452400920 10020565501150 20041131002300 25051413752875 40082262004600 50102827505750 100205655011500 200411310023000