Base | Representation |
---|---|
bin | 10010101010100011… |
… | …100100111101001101 |
3 | 1220201201021122210221 |
4 | 102222203210331031 |
5 | 312021034303232 |
6 | 13112403031341 |
7 | 1306433300062 |
oct | 225243447515 |
9 | 56651248727 |
10 | 20041322317 |
11 | 85548930a5 |
12 | 3a7396b551 |
13 | 1b75115303 |
14 | d819a0c69 |
15 | 7c46ce897 |
hex | 4aa8e4f4d |
20041322317 has 2 divisors, whose sum is σ = 20041322318. Its totient is φ = 20041322316.
The previous prime is 20041322293. The next prime is 20041322363. The reversal of 20041322317 is 71322314002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16928351881 + 3112970436 = 130109^2 + 55794^2 .
It is a cyclic number.
It is not a de Polignac number, because 20041322317 - 211 = 20041320269 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20041322291 and 20041322300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20041322017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10020661158 + 10020661159.
It is an arithmetic number, because the mean of its divisors is an integer number (10020661159).
Almost surely, 220041322317 is an apocalyptic number.
It is an amenable number.
20041322317 is a deficient number, since it is larger than the sum of its proper divisors (1).
20041322317 is an equidigital number, since it uses as much as digits as its factorization.
20041322317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 20041322317 its reverse (71322314002), we get a palindrome (91363636319).
The spelling of 20041322317 in words is "twenty billion, forty-one million, three hundred twenty-two thousand, three hundred seventeen".
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