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200521433113 is a prime number
BaseRepresentation
bin1011101011000000000…
…0100100000000011001
3201011120200110020020221
42322300000210000121
511241131441324423
6232041314120041
720326052026111
oct2726000440031
9634520406227
10200521433113
117804a137661
1232a42280021
1315ba8369a91
1499c3456041
155339122e5d
hex2eb0024019

200521433113 has 2 divisors, whose sum is σ = 200521433114. Its totient is φ = 200521433112.

The previous prime is 200521433111. The next prime is 200521433143. The reversal of 200521433113 is 311334125002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 200420068489 + 101364624 = 447683^2 + 10068^2 .

It is a cyclic number.

It is not a de Polignac number, because 200521433113 - 21 = 200521433111 is a prime.

Together with 200521433111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (200521433111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100260716556 + 100260716557.

It is an arithmetic number, because the mean of its divisors is an integer number (100260716557).

Almost surely, 2200521433113 is an apocalyptic number.

It is an amenable number.

200521433113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200521433113 is an equidigital number, since it uses as much as digits as its factorization.

200521433113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 200521433113 its reverse (311334125002), we get a palindrome (511855558115).

The spelling of 200521433113 in words is "two hundred billion, five hundred twenty-one million, four hundred thirty-three thousand, one hundred thirteen".