Base | Representation |
---|---|
bin | 1011101011000000000… |
… | …0100100000000011001 |
3 | 201011120200110020020221 |
4 | 2322300000210000121 |
5 | 11241131441324423 |
6 | 232041314120041 |
7 | 20326052026111 |
oct | 2726000440031 |
9 | 634520406227 |
10 | 200521433113 |
11 | 7804a137661 |
12 | 32a42280021 |
13 | 15ba8369a91 |
14 | 99c3456041 |
15 | 5339122e5d |
hex | 2eb0024019 |
200521433113 has 2 divisors, whose sum is σ = 200521433114. Its totient is φ = 200521433112.
The previous prime is 200521433111. The next prime is 200521433143. The reversal of 200521433113 is 311334125002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 200420068489 + 101364624 = 447683^2 + 10068^2 .
It is a cyclic number.
It is not a de Polignac number, because 200521433113 - 21 = 200521433111 is a prime.
Together with 200521433111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (200521433111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100260716556 + 100260716557.
It is an arithmetic number, because the mean of its divisors is an integer number (100260716557).
Almost surely, 2200521433113 is an apocalyptic number.
It is an amenable number.
200521433113 is a deficient number, since it is larger than the sum of its proper divisors (1).
200521433113 is an equidigital number, since it uses as much as digits as its factorization.
200521433113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 200521433113 its reverse (311334125002), we get a palindrome (511855558115).
The spelling of 200521433113 in words is "two hundred billion, five hundred twenty-one million, four hundred thirty-three thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •