Base | Representation |
---|---|
bin | 101101101110011010110101… |
… | …010110000101111111001101 |
3 | 222101001011102020022101010110 |
4 | 231232122311112011333031 |
5 | 202324323344301413401 |
6 | 1551412552311430233 |
7 | 60234066030055560 |
oct | 5556326526057715 |
9 | 871034366271113 |
10 | 201102001201101 |
11 | 59093974a61350 |
12 | 1a67aab9385379 |
13 | 8829ab6842100 |
14 | 3793562bba4d7 |
15 | 183b1d058d9d6 |
hex | b6e6b5585fcd |
201102001201101 has 96 divisors (see below), whose sum is σ = 370411316554752. Its totient is φ = 94189910330880.
The previous prime is 201102001200917. The next prime is 201102001201117. The reversal of 201102001201101 is 101102100201102.
It is not a de Polignac number, because 201102001201101 - 215 = 201102001168333 is a prime.
It is a super-2 number, since 2×2011020012011012 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201102001201121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 58220280 + ... + 61577633.
It is an arithmetic number, because the mean of its divisors is an integer number (3858451214112).
Almost surely, 2201102001201101 is an apocalyptic number.
201102001201101 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
201102001201101 is a deficient number, since it is larger than the sum of its proper divisors (169309315353651).
201102001201101 is a wasteful number, since it uses less digits than its factorization.
201102001201101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119798003 (or 119797990 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 201102001201101 its reverse (101102100201102), we get a palindrome (302204101402203).
Subtracting from 201102001201101 its reverse (101102100201102), we obtain a palindrome (99999900999999).
It can be divided in two parts, 201102001 and 201101, that added together give a palindrome (201303102).
The spelling of 201102001201101 in words is "two hundred one trillion, one hundred two billion, one million, two hundred one thousand, one hundred one".
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