Base | Representation |
---|---|
bin | 11101010000111011100… |
… | …100011011011110111111 |
3 | 21010020212010021021001222 |
4 | 131100323210123132333 |
5 | 230422104242200111 |
6 | 4135505542223555 |
7 | 265202355543311 |
oct | 35207344333677 |
9 | 7106763237058 |
10 | 2011044100031 |
11 | 705973a6a68a |
12 | 285906724bbb |
13 | 11784365c7c5 |
14 | 6d49955d7b1 |
15 | 374a287d7db |
hex | 1d43b91b7bf |
2011044100031 has 2 divisors, whose sum is σ = 2011044100032. Its totient is φ = 2011044100030.
The previous prime is 2011044099943. The next prime is 2011044100067. The reversal of 2011044100031 is 1300014401102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011044100031 is a prime.
It is a super-2 number, since 2×20110441000312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2011044099982 and 2011044100009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011044106031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005522050015 + 1005522050016.
It is an arithmetic number, because the mean of its divisors is an integer number (1005522050016).
Almost surely, 22011044100031 is an apocalyptic number.
2011044100031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011044100031 is an equidigital number, since it uses as much as digits as its factorization.
2011044100031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2011044100031 its reverse (1300014401102), we get a palindrome (3311058501133).
The spelling of 2011044100031 in words is "two trillion, eleven billion, forty-four million, one hundred thousand, thirty-one".
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