Base | Representation |
---|---|
bin | 1001001001010101101101… |
… | …01001000111000111111111 |
3 | 2122012200211220110221110202 |
4 | 10210222312221013013333 |
5 | 10114004040341012041 |
6 | 110435212141554115 |
7 | 4144023420522152 |
oct | 444526651070777 |
9 | 78180756427422 |
10 | 20112101110271 |
11 | 6454548834415 |
12 | 2309a39b7593b |
13 | b2b741b99c51 |
14 | 4d76064d9c99 |
15 | 24d266664a9b |
hex | 124ab6a471ff |
20112101110271 has 2 divisors, whose sum is σ = 20112101110272. Its totient is φ = 20112101110270.
The previous prime is 20112101110141. The next prime is 20112101110273. The reversal of 20112101110271 is 17201110121102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20112101110271 - 218 = 20112100848127 is a prime.
It is a super-2 number, since 2×201121011102712 (a number of 27 digits) contains 22 as substring.
Together with 20112101110273, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20112101110273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056050555135 + 10056050555136.
It is an arithmetic number, because the mean of its divisors is an integer number (10056050555136).
Almost surely, 220112101110271 is an apocalyptic number.
20112101110271 is a deficient number, since it is larger than the sum of its proper divisors (1).
20112101110271 is an equidigital number, since it uses as much as digits as its factorization.
20112101110271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 20112101110271 its reverse (17201110121102), we get a palindrome (37313211231373).
The spelling of 20112101110271 in words is "twenty trillion, one hundred twelve billion, one hundred one million, one hundred ten thousand, two hundred seventy-one".
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