Base | Representation |
---|---|
bin | 101101101110111000110000… |
… | …010111111001010011110111 |
3 | 222101011020100100101121100121 |
4 | 231232320300113321103313 |
5 | 202330340144242321403 |
6 | 1551435424352152411 |
7 | 60236314146522136 |
oct | 5556706027712367 |
9 | 871136310347317 |
10 | 201134130042103 |
11 | 590a6561942105 |
12 | 1a685185238707 |
13 | 882cb36c8262b |
14 | 3794d2dc5b91d |
15 | 183be6102a3bd |
hex | b6ee305f94f7 |
201134130042103 has 2 divisors, whose sum is σ = 201134130042104. Its totient is φ = 201134130042102.
The previous prime is 201134130042101. The next prime is 201134130042127. The reversal of 201134130042103 is 301240031431102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201134130042103 - 21 = 201134130042101 is a prime.
Together with 201134130042101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201134130042101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100567065021051 + 100567065021052.
It is an arithmetic number, because the mean of its divisors is an integer number (100567065021052).
Almost surely, 2201134130042103 is an apocalyptic number.
201134130042103 is a deficient number, since it is larger than the sum of its proper divisors (1).
201134130042103 is an equidigital number, since it uses as much as digits as its factorization.
201134130042103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 201134130042103 its reverse (301240031431102), we get a palindrome (502374161473205).
The spelling of 201134130042103 in words is "two hundred one trillion, one hundred thirty-four billion, one hundred thirty million, forty-two thousand, one hundred three".
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