Base | Representation |
---|---|
bin | 1011101101100010000… |
… | …1010101010000111111 |
3 | 201020100001101111120202 |
4 | 2323120201111100333 |
5 | 11244024441042002 |
6 | 232232554034115 |
7 | 20351644143431 |
oct | 2733041252077 |
9 | 636301344522 |
10 | 201201112127 |
11 | 78368867554 |
12 | 32bb1a1893b |
13 | 15c86112902 |
14 | 9a49820651 |
15 | 5378b2e502 |
hex | 2ed885543f |
201201112127 has 2 divisors, whose sum is σ = 201201112128. Its totient is φ = 201201112126.
The previous prime is 201201112121. The next prime is 201201112153. The reversal of 201201112127 is 721211102102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201201112127 - 24 = 201201112111 is a prime.
It is a super-2 number, since 2×2012011121272 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201201112099 and 201201112108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201201112121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100600556063 + 100600556064.
It is an arithmetic number, because the mean of its divisors is an integer number (100600556064).
Almost surely, 2201201112127 is an apocalyptic number.
201201112127 is a deficient number, since it is larger than the sum of its proper divisors (1).
201201112127 is an equidigital number, since it uses as much as digits as its factorization.
201201112127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 201201112127 its reverse (721211102102), we get a palindrome (922412214229).
The spelling of 201201112127 in words is "two hundred one billion, two hundred one million, one hundred twelve thousand, one hundred twenty-seven".
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