Base | Representation |
---|---|
bin | 1001001001101000001010… |
… | …10101001011100011010111 |
3 | 2122020122102120002200120121 |
4 | 10210310011111023203113 |
5 | 10114134334333021213 |
6 | 110443531354012411 |
7 | 4144524124206655 |
oct | 444640525134327 |
9 | 78218376080517 |
10 | 20122011220183 |
11 | 64587738326a4 |
12 | 230b944a17107 |
13 | b2c661073502 |
14 | 4d7ca673ddd5 |
15 | 24d6466b888d |
hex | 124d0554b8d7 |
20122011220183 has 2 divisors, whose sum is σ = 20122011220184. Its totient is φ = 20122011220182.
The previous prime is 20122011220097. The next prime is 20122011220193. The reversal of 20122011220183 is 38102211022102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20122011220183 - 29 = 20122011219671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20122011220193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061005610091 + 10061005610092.
It is an arithmetic number, because the mean of its divisors is an integer number (10061005610092).
Almost surely, 220122011220183 is an apocalyptic number.
20122011220183 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122011220183 is an equidigital number, since it uses as much as digits as its factorization.
20122011220183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 20122011220183 its reverse (38102211022102), we get a palindrome (58224222242285).
The spelling of 20122011220183 in words is "twenty trillion, one hundred twenty-two billion, eleven million, two hundred twenty thousand, one hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •