Base | Representation |
---|---|
bin | 1001001001101010001111… |
… | …00110101110000000100111 |
3 | 2122020202022001022202011221 |
4 | 10210311013212232000213 |
5 | 10114144124004122043 |
6 | 110444233553441211 |
7 | 4144563515150656 |
oct | 444650746560047 |
9 | 78222261282157 |
10 | 20123123114023 |
11 | 6459194430a26 |
12 | 230bbb5270207 |
13 | b2c7aa529a67 |
14 | 4d7d7029719d |
15 | 24d6ae0ed8ed |
hex | 124d479ae027 |
20123123114023 has 2 divisors, whose sum is σ = 20123123114024. Its totient is φ = 20123123114022.
The previous prime is 20123123114021. The next prime is 20123123114033. The reversal of 20123123114023 is 32041132132102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20123123114023 - 21 = 20123123114021 is a prime.
Together with 20123123114021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20123123114021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061561557011 + 10061561557012.
It is an arithmetic number, because the mean of its divisors is an integer number (10061561557012).
Almost surely, 220123123114023 is an apocalyptic number.
20123123114023 is a deficient number, since it is larger than the sum of its proper divisors (1).
20123123114023 is an equidigital number, since it uses as much as digits as its factorization.
20123123114023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 20123123114023 its reverse (32041132132102), we get a palindrome (52164255246125).
The spelling of 20123123114023 in words is "twenty trillion, one hundred twenty-three billion, one hundred twenty-three million, one hundred fourteen thousand, twenty-three".
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