Base | Representation |
---|---|
bin | 1001001001111001001011… |
… | …01100000011100000000110 |
3 | 2122021112000001002002110120 |
4 | 10210330211230003200012 |
5 | 10114312040332201042 |
6 | 110452041521402410 |
7 | 4145266341561255 |
oct | 444744554034006 |
9 | 78245001062416 |
10 | 20131144022022 |
11 | 646162aa89910 |
12 | 2311673499406 |
13 | b304881b0677 |
14 | 4d84d164479c |
15 | 24d9cd378dec |
hex | 124f25b03806 |
20131144022022 has 64 divisors (see below), whose sum is σ = 44045926170624. Its totient is φ = 6083206446240.
The previous prime is 20131144021949. The next prime is 20131144022063. The reversal of 20131144022022 is 22022044113102.
It is a junction number, because it is equal to n+sod(n) for n = 20131144021983 and 20131144022001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 360080523 + ... + 360136425.
It is an arithmetic number, because the mean of its divisors is an integer number (688217596416).
Almost surely, 220131144022022 is an apocalyptic number.
20131144022022 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
20131144022022 is an abundant number, since it is smaller than the sum of its proper divisors (23914782148602).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20131144022022 is a wasteful number, since it uses less digits than its factorization.
20131144022022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71153.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 20131144022022 its reverse (22022044113102), we get a palindrome (42153188135124).
The spelling of 20131144022022 in words is "twenty trillion, one hundred thirty-one billion, one hundred forty-four million, twenty-two thousand, twenty-two".
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