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201330202122151 is a prime number
BaseRepresentation
bin101101110001101111010111…
…001011100001011110100111
3222101211222102221121021122021
4231301233113023201132213
5202342043223220402101
61552105452405244011
760256425043641364
oct5561572713413647
9871758387537567
10201330202122151
1159171728480973
121a6b7185403607
1388454835995cb
1437a06103cd46b
1518420d97165a1
hexb71bd72e17a7

201330202122151 has 2 divisors, whose sum is σ = 201330202122152. Its totient is φ = 201330202122150.

The previous prime is 201330202122149. The next prime is 201330202122163. The reversal of 201330202122151 is 151221202033102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201330202122151 - 21 = 201330202122149 is a prime.

Together with 201330202122149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201330202122191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100665101061075 + 100665101061076.

It is an arithmetic number, because the mean of its divisors is an integer number (100665101061076).

Almost surely, 2201330202122151 is an apocalyptic number.

201330202122151 is a deficient number, since it is larger than the sum of its proper divisors (1).

201330202122151 is an equidigital number, since it uses as much as digits as its factorization.

201330202122151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 201330202122151 its reverse (151221202033102), we get a palindrome (352551404155253).

The spelling of 201330202122151 in words is "two hundred one trillion, three hundred thirty billion, two hundred two million, one hundred twenty-two thousand, one hundred fifty-one".