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20133211031447 is a prime number
BaseRepresentation
bin1001001001111101000001…
…11001000100011110010111
32122021201100002112001100012
410210332200321010132113
510114330304011001242
6110453023000510435
74145401511062643
oct444764071043627
978251302461305
1020133211031447
1164624a0834668
122311b4b77b41b
13b307274ba277
144d8649d83c23
1524da9ea76282
hex124fa0e44797

20133211031447 has 2 divisors, whose sum is σ = 20133211031448. Its totient is φ = 20133211031446.

The previous prime is 20133211031431. The next prime is 20133211031449. The reversal of 20133211031447 is 74413011233102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20133211031447 - 24 = 20133211031431 is a prime.

Together with 20133211031449, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20133211031449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066605515723 + 10066605515724.

It is an arithmetic number, because the mean of its divisors is an integer number (10066605515724).

Almost surely, 220133211031447 is an apocalyptic number.

20133211031447 is a deficient number, since it is larger than the sum of its proper divisors (1).

20133211031447 is an equidigital number, since it uses as much as digits as its factorization.

20133211031447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 20133211031447 its reverse (74413011233102), we get a palindrome (94546222264549).

The spelling of 20133211031447 in words is "twenty trillion, one hundred thirty-three billion, two hundred eleven million, thirty-one thousand, four hundred forty-seven".