Base | Representation |
---|---|
bin | 11101010011000011111… |
… | …000110001011001011000 |
3 | 21010110202111201121221021 |
4 | 131103003320301121120 |
5 | 230441300232242130 |
6 | 4140524521252224 |
7 | 265313136163042 |
oct | 35230370613130 |
9 | 7113674647837 |
10 | 2013331134040 |
11 | 706937a35136 |
12 | 286244634074 |
13 | 117b19415075 |
14 | 6d6351b4a92 |
15 | 3758853d37a |
hex | 1d4c3e31658 |
2013331134040 has 32 divisors (see below), whose sum is σ = 4635343777680. Its totient is φ = 786603791232.
The previous prime is 2013331134037. The next prime is 2013331134079. The reversal of 2013331134040 is 404311333102.
It is a junction number, because it is equal to n+sod(n) for n = 2013331133996 and 2013331134014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 585268959 + ... + 585272398.
Almost surely, 22013331134040 is an apocalyptic number.
2013331134040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2013331134040 is an abundant number, since it is smaller than the sum of its proper divisors (2622012643640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013331134040 is a wasteful number, since it uses less digits than its factorization.
2013331134040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1170541411 (or 1170541407 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2013331134040 its reverse (404311333102), we get a palindrome (2417642467142).
The spelling of 2013331134040 in words is "two trillion, thirteen billion, three hundred thirty-one million, one hundred thirty-four thousand, forty".
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