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20134410557 is a prime number
BaseRepresentation
bin10010110000000110…
…101011100100111101
31220222012110000212112
4102300012223210331
5312213402114212
613125530143405
71311643444262
oct226006534475
956865400775
1020134410557
1185a2393728
123a9ab81b65
131b8b4a8b01
14d900b3269
157cc96b422
hex4b01ab93d

20134410557 has 2 divisors, whose sum is σ = 20134410558. Its totient is φ = 20134410556.

The previous prime is 20134410529. The next prime is 20134410559. The reversal of 20134410557 is 75501443102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18176702041 + 1957708516 = 134821^2 + 44246^2 .

It is a cyclic number.

It is not a de Polignac number, because 20134410557 - 28 = 20134410301 is a prime.

Together with 20134410559, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20134410559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067205278 + 10067205279.

It is an arithmetic number, because the mean of its divisors is an integer number (10067205279).

Almost surely, 220134410557 is an apocalyptic number.

It is an amenable number.

20134410557 is a deficient number, since it is larger than the sum of its proper divisors (1).

20134410557 is an equidigital number, since it uses as much as digits as its factorization.

20134410557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 32.

Adding to 20134410557 its reverse (75501443102), we get a palindrome (95635853659).

The spelling of 20134410557 in words is "twenty billion, one hundred thirty-four million, four hundred ten thousand, five hundred fifty-seven".