Base | Representation |
---|---|
bin | 10010110001000111… |
… | …101110010010011111 |
3 | 1221000101112021201021 |
4 | 102301013232102133 |
5 | 312232233223043 |
6 | 13131335425011 |
7 | 1312241410141 |
oct | 226107562237 |
9 | 57011467637 |
10 | 20151461023 |
11 | 8600a79a21 |
12 | 3aa4825167 |
13 | 1b91b98845 |
14 | d92470c91 |
15 | 7ce1d83ed |
hex | 4b11ee49f |
20151461023 has 2 divisors, whose sum is σ = 20151461024. Its totient is φ = 20151461022.
The previous prime is 20151460991. The next prime is 20151461027. The reversal of 20151461023 is 32016415102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20151461023 - 25 = 20151460991 is a prime.
It is a super-2 number, since 2×201514610232 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20151461027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10075730511 + 10075730512.
It is an arithmetic number, because the mean of its divisors is an integer number (10075730512).
Almost surely, 220151461023 is an apocalyptic number.
20151461023 is a deficient number, since it is larger than the sum of its proper divisors (1).
20151461023 is an equidigital number, since it uses as much as digits as its factorization.
20151461023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 20151461023 its reverse (32016415102), we get a palindrome (52167876125).
The spelling of 20151461023 in words is "twenty billion, one hundred fifty-one million, four hundred sixty-one thousand, twenty-three".
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