Base | Representation |
---|---|
bin | 10010110001001101… |
… | …101001000001111111 |
3 | 1221000111110002201212 |
4 | 102301031221001333 |
5 | 312233132343401 |
6 | 13131432555035 |
7 | 1312260531023 |
oct | 226115510177 |
9 | 57014402655 |
10 | 20153012351 |
11 | 860193950a |
12 | 3aa5252a7b |
13 | 1b922bc9a4 |
14 | d92756383 |
15 | 7ce3e2dbb |
hex | 4b136907f |
20153012351 has 2 divisors, whose sum is σ = 20153012352. Its totient is φ = 20153012350.
The previous prime is 20153012309. The next prime is 20153012353. The reversal of 20153012351 is 15321035102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20153012351 is a prime.
It is a super-2 number, since 2×201530123512 (a number of 21 digits) contains 22 as substring.
Together with 20153012353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20153012353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076506175 + 10076506176.
It is an arithmetic number, because the mean of its divisors is an integer number (10076506176).
Almost surely, 220153012351 is an apocalyptic number.
20153012351 is a deficient number, since it is larger than the sum of its proper divisors (1).
20153012351 is an equidigital number, since it uses as much as digits as its factorization.
20153012351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 20153012351 its reverse (15321035102), we get a palindrome (35474047453).
The spelling of 20153012351 in words is "twenty billion, one hundred fifty-three million, twelve thousand, three hundred fifty-one".
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