Base | Representation |
---|---|
bin | 1001001010110100111111… |
… | …00111001101110100100111 |
3 | 2122101120212212022111201221 |
4 | 10211122133213031310213 |
5 | 10120323321103014444 |
6 | 110514512101201211 |
7 | 4150514145040243 |
oct | 445323747156447 |
9 | 78346785274657 |
10 | 20163254344999 |
11 | 6474208471817 |
12 | 2317935100207 |
13 | b3350483918c |
14 | 4d9c9a065423 |
15 | 24e75c3a8a84 |
hex | 12569f9cdd27 |
20163254344999 has 2 divisors, whose sum is σ = 20163254345000. Its totient is φ = 20163254344998.
The previous prime is 20163254344963. The next prime is 20163254345009. The reversal of 20163254344999 is 99944345236102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20163254344999 - 219 = 20163253820711 is a prime.
It is a super-2 number, since 2×201632543449992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20163254344199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10081627172499 + 10081627172500.
It is an arithmetic number, because the mean of its divisors is an integer number (10081627172500).
Almost surely, 220163254344999 is an apocalyptic number.
20163254344999 is a deficient number, since it is larger than the sum of its proper divisors (1).
20163254344999 is an equidigital number, since it uses as much as digits as its factorization.
20163254344999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50388480, while the sum is 61.
The spelling of 20163254344999 in words is "twenty trillion, one hundred sixty-three billion, two hundred fifty-four million, three hundred forty-four thousand, nine hundred ninety-nine".
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