Base | Representation |
---|---|
bin | 1001001010110100111111… |
… | …00111001101110100101000 |
3 | 2122101120212212022111201222 |
4 | 10211122133213031310220 |
5 | 10120323321103020000 |
6 | 110514512101201212 |
7 | 4150514145040244 |
oct | 445323747156450 |
9 | 78346785274658 |
10 | 20163254345000 |
11 | 6474208471818 |
12 | 2317935100208 |
13 | b33504839190 |
14 | 4d9c9a065424 |
15 | 24e75c3a8a85 |
hex | 12569f9cdd28 |
20163254345000 has 160 divisors (see below), whose sum is σ = 53869284592200. Its totient is φ = 7006958592000.
The previous prime is 20163254344999. The next prime is 20163254345009. The reversal of 20163254345000 is 54345236102.
It can be written as a sum of positive squares in 20 ways, for example, as 2749342036996 + 17413912308004 = 1658114^2 + 4172998^2 .
It is a super-2 number, since 2×201632543450002 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (20163254345009) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 8018645 + ... + 10228644.
Almost surely, 220163254345000 is an apocalyptic number.
20163254345000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
20163254345000 is an abundant number, since it is smaller than the sum of its proper divisors (33706030247200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20163254345000 is a wasteful number, since it uses less digits than its factorization.
20163254345000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18247345 (or 18247326 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 20163254345000 in words is "twenty trillion, one hundred sixty-three billion, two hundred fifty-four million, three hundred forty-five thousand".
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