Base | Representation |
---|---|
bin | 1001001011011110111000… |
… | …00101100101010100100101 |
3 | 2122110201221012010220222022 |
4 | 10211233130011211110211 |
5 | 10121210400401300023 |
6 | 110533111435512525 |
7 | 4152241356040505 |
oct | 445573405452445 |
9 | 78421835126868 |
10 | 20185743775013 |
11 | 64827a9135413 |
12 | 23201708b8745 |
13 | b35679bb210b |
14 | 4dadd0c09a05 |
15 | 2501269637c8 |
hex | 125bdc165525 |
20185743775013 has 2 divisors, whose sum is σ = 20185743775014. Its totient is φ = 20185743775012.
The previous prime is 20185743774983. The next prime is 20185743775037. The reversal of 20185743775013 is 31057734758102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12730752448324 + 7454991326689 = 3568018^2 + 2730383^2 .
It is a cyclic number.
It is not a de Polignac number, because 20185743775013 - 222 = 20185739580709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20185743775313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10092871887506 + 10092871887507.
It is an arithmetic number, because the mean of its divisors is an integer number (10092871887507).
Almost surely, 220185743775013 is an apocalyptic number.
It is an amenable number.
20185743775013 is a deficient number, since it is larger than the sum of its proper divisors (1).
20185743775013 is an equidigital number, since it uses as much as digits as its factorization.
20185743775013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4939200, while the sum is 53.
The spelling of 20185743775013 in words is "twenty trillion, one hundred eighty-five billion, seven hundred forty-three million, seven hundred seventy-five thousand, thirteen".
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