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202042423044151 is a prime number
BaseRepresentation
bin101101111100000110101010…
…110110101110100000110111
3222111101001210211220211201221
4231330012222312232200313
5202440230340244403101
61553413001403331211
760362040406615204
oct5574065266564067
9874331724824657
10202042423044151
115941678a6340a8
121a7b1212820b07
13889769889c331
1437c6c967bccab
1518558c162caa1
hexb7c1aadae837

202042423044151 has 2 divisors, whose sum is σ = 202042423044152. Its totient is φ = 202042423044150.

The previous prime is 202042423044149. The next prime is 202042423044157. The reversal of 202042423044151 is 151440324240202.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 202042423044151 - 21 = 202042423044149 is a prime.

It is a super-3 number, since 3×2020424230441513 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 202042423044149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202042423044157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101021211522075 + 101021211522076.

It is an arithmetic number, because the mean of its divisors is an integer number (101021211522076).

Almost surely, 2202042423044151 is an apocalyptic number.

202042423044151 is a deficient number, since it is larger than the sum of its proper divisors (1).

202042423044151 is an equidigital number, since it uses as much as digits as its factorization.

202042423044151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61440, while the sum is 34.

Adding to 202042423044151 its reverse (151440324240202), we get a palindrome (353482747284353).

The spelling of 202042423044151 in words is "two hundred two trillion, forty-two billion, four hundred twenty-three million, forty-four thousand, one hundred fifty-one".