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202111313100 = 223521097961363
BaseRepresentation
bin1011110000111011000…
…1011110010011001100
3201022200111002111120220
42330032301132103030
511302410444004400
6232503150511340
720413335546534
oct2741661362314
9638614074526
10202111313100
1178795626a64
1233206805550
131609c86b478
149ad46744c4
1553cd9c37a0
hex2f0ec5e4cc

202111313100 has 72 divisors (see below), whose sum is σ = 584838192960. Its totient is φ = 53890562880.

The previous prime is 202111313093. The next prime is 202111313101. The reversal of 202111313100 is 1313111202.

It is a happy number.

202111313100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×2021113131002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 202111313100.

It is not an unprimeable number, because it can be changed into a prime (202111313101) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3263019 + ... + 3324381.

It is an arithmetic number, because the mean of its divisors is an integer number (8122752680).

Almost surely, 2202111313100 is an apocalyptic number.

202111313100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

202111313100 is an abundant number, since it is smaller than the sum of its proper divisors (382726879860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

202111313100 is a wasteful number, since it uses less digits than its factorization.

202111313100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72359 (or 72352 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 202111313100 its reverse (1313111202), we get a palindrome (203424424302).

The spelling of 202111313100 in words is "two hundred two billion, one hundred eleven million, three hundred thirteen thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 150 300 10979 21958 32937 43916 54895 61363 65874 109790 122726 131748 164685 184089 219580 245452 274475 306815 329370 368178 548950 613630 658740 736356 823425 920445 1097900 1227260 1534075 1646850 1840890 3068150 3293700 3681780 4602225 6136300 9204450 18408900 673704377 1347408754 2021113131 2694817508 3368521885 4042226262 6737043770 8084452524 10105565655 13474087540 16842609425 20211131310 33685218850 40422262620 50527828275 67370437700 101055656550 202111313100