20211201301 has 2 divisors, whose sum is σ = 20211201302. Its totient is φ = 20211201300.

The previous prime is 20211201299. The next prime is 20211201317. The reversal of 20211201301 is 10310211202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18913400676 + 1297800625 = 137526^2 + 36025^2 .

It is a cyclic number.

It is not a de Polignac number, because 20211201301 - 2¹ = 20211201299 is a prime.

Together with 20211201299, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20211201331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105600650 + 10105600651.

It is an arithmetic number, because the mean of its divisors is an integer number (10105600651).

Almost surely, 2^20211201301 is an apocalyptic number.

It is an amenable number.

20211201301 is a deficient number, since it is larger than the sum of its proper divisors (1).

20211201301 is an equidigital number, since it uses as much as digits as its factorization.

20211201301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20211201301 its reverse (10310211202), we get a palindrome (30521412503).

Subtracting from 20211201301 its reverse (10310211202), we obtain a palindrome (9900990099).

The spelling of 20211201301 in words is "twenty billion, two hundred eleven million, two hundred one thousand, three hundred one".