Base | Representation |
---|---|
bin | 10010110101011110… |
… | …000000001101000001 |
3 | 1221012110210111111021 |
4 | 102311132000031001 |
5 | 312404422113213 |
6 | 13142503145441 |
7 | 1314115436503 |
oct | 226536001501 |
9 | 57173714437 |
10 | 20224410433 |
11 | 8639174997 |
12 | 3b05145281 |
13 | 1ba402a986 |
14 | d9c01dd73 |
15 | 7d57e7d8d |
hex | 4b5780341 |
20224410433 has 2 divisors, whose sum is σ = 20224410434. Its totient is φ = 20224410432.
The previous prime is 20224410431. The next prime is 20224410449. The reversal of 20224410433 is 33401442202.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19481738929 + 742671504 = 139577^2 + 27252^2 .
It is a cyclic number.
It is not a de Polignac number, because 20224410433 - 21 = 20224410431 is a prime.
Together with 20224410431, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 20224410398 and 20224410407.
It is not a weakly prime, because it can be changed into another prime (20224410431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10112205216 + 10112205217.
It is an arithmetic number, because the mean of its divisors is an integer number (10112205217).
Almost surely, 220224410433 is an apocalyptic number.
It is an amenable number.
20224410433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20224410433 is an equidigital number, since it uses as much as digits as its factorization.
20224410433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 20224410433 its reverse (33401442202), we get a palindrome (53625852635).
The spelling of 20224410433 in words is "twenty billion, two hundred twenty-four million, four hundred ten thousand, four hundred thirty-three".
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