2050312135125 has 128 divisors (see below), whose sum is σ = 3638925388800. Its totient is φ = 1022911718400.

The previous prime is 2050312135117. The next prime is 2050312135139. The reversal of 2050312135125 is 5215312130502.

It is not a de Polignac number, because 2050312135125 - 2³ = 2050312135117 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2050312135092 and 2050312135101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 144901551 + ... + 144915699.

It is an arithmetic number, because the mean of its divisors is an integer number (28429104600).

Almost surely, 2^{2050312135125} is an apocalyptic number.

2050312135125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

2050312135125 is a deficient number, since it is larger than the sum of its proper divisors (1588613253675).

2050312135125 is a wasteful number, since it uses less digits than its factorization.

2050312135125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14560 (or 14550 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 2050312135125 its reverse (5215312130502), we get a palindrome (7265624265627).

The spelling of 2050312135125 in words is "two trillion, fifty billion, three hundred twelve million, one hundred thirty-five thousand, one hundred twenty-five".