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210013004314100 = 225213212426804989
BaseRepresentation
bin101111110000000101110110…
…100001010011010111110100
31000112121001021100202220200202
4233300011312201103113310
5210011323113101022400
62022354350422100032
762143640011555241
oct5760056641232764
91015531240686622
10210013004314100
1160a0a0189a8a99
121b679b1627a618
1390251ab669900
1439c097dcc25c8
151942dc09d74d5
hexbf01768535f4

210013004314100 has 54 divisors (see below), whose sum is σ = 493480852957890. Its totient is φ = 77543263125120.

The previous prime is 210013004314079. The next prime is 210013004314103. The reversal of 210013004314100 is 1413400310012.

It can be written as a sum of positive squares in 9 ways, for example, as 181590393900304 + 28422610413796 = 13475548^2 + 5331286^2 .

It is a super-2 number, since 2×2100130043141002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210013004314103) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 6213385595 + ... + 6213419394.

It is an arithmetic number, because the mean of its divisors is an integer number (9138534314035).

Almost surely, 2210013004314100 is an apocalyptic number.

210013004314100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

210013004314100 is an abundant number, since it is smaller than the sum of its proper divisors (283467848643790).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

210013004314100 is a wasteful number, since it uses less digits than its factorization.

210013004314100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12426805029 (or 12426805009 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 210013004314100 its reverse (1413400310012), we get a palindrome (211426404624112).

The spelling of 210013004314100 in words is "two hundred ten trillion, thirteen billion, four million, three hundred fourteen thousand, one hundred".

Divisors: 1 2 4 5 10 13 20 25 26 50 52 65 100 130 169 260 325 338 650 676 845 1300 1690 3380 4225 8450 16900 12426804989 24853609978 49707219956 62134024945 124268049890 161548464857 248536099780 310670124725 323096929714 621340249450 646193859428 807742324285 1242680498900 1615484648570 2100130043141 3230969297140 4038711621425 4200260086282 8077423242850 8400520172564 10500650215705 16154846485700 21001300431410 42002600862820 52503251078525 105006502157050 210013004314100