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2100314055004 = 221168369889327
BaseRepresentation
bin11110100100000100011…
…110010010000101011100
321102210021111102211200121
4132210010132102011130
5233402420344230004
64244512043204324
7304512511621564
oct36440436220534
97383244384617
102100314055004
1173a813590080
1229b07ab166a4
1312309c153079
1473927501da4
1539979aa0854
hex1e90479215c

2100314055004 has 24 divisors (see below), whose sum is σ = 4015561229568. Its totient is φ = 953290406640.

The previous prime is 2100314054957. The next prime is 2100314055017. The reversal of 2100314055004 is 4005504130012.

It is a happy number.

It is a super-2 number, since 2×21003140550042 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2100314055004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34914612 + ... + 34974715.

It is an arithmetic number, because the mean of its divisors is an integer number (167315051232).

Almost surely, 22100314055004 is an apocalyptic number.

It is an amenable number.

2100314055004 is a deficient number, since it is larger than the sum of its proper divisors (1915247174564).

2100314055004 is a wasteful number, since it uses less digits than its factorization.

2100314055004 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69890025 (or 69890023 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 2100314055004 its reverse (4005504130012), we get a palindrome (6105818185016).

The spelling of 2100314055004 in words is "two trillion, one hundred billion, three hundred fourteen million, fifty-five thousand, four".

Divisors: 1 2 4 11 22 44 683 1366 2732 7513 15026 30052 69889327 139778654 279557308 768782597 1537565194 3075130388 47734410341 95468820682 190937641364 525078513751 1050157027502 2100314055004