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21043245351343 is a prime number
BaseRepresentation
bin1001100100011100000110…
…01010100000000110101111
32202111201021221122101202011
410302032003022200012233
510224233031302220333
6112431044454342051
74301216144135305
oct462160312400657
982451257571664
1021043245351343
11678343244a516
12243a3a435a927
13b984a5abbb67
1452a6d9ca4275
152675b2e8e9cd
hex1323832a01af

21043245351343 has 2 divisors, whose sum is σ = 21043245351344. Its totient is φ = 21043245351342.

The previous prime is 21043245351341. The next prime is 21043245351371. The reversal of 21043245351343 is 34315354234012.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21043245351343 - 21 = 21043245351341 is a prime.

Together with 21043245351341, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 21043245351296 and 21043245351305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21043245351341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10521622675671 + 10521622675672.

It is an arithmetic number, because the mean of its divisors is an integer number (10521622675672).

Almost surely, 221043245351343 is an apocalyptic number.

21043245351343 is a deficient number, since it is larger than the sum of its proper divisors (1).

21043245351343 is an equidigital number, since it uses as much as digits as its factorization.

21043245351343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 21043245351343 its reverse (34315354234012), we get a palindrome (55358599585355).

The spelling of 21043245351343 in words is "twenty-one trillion, forty-three billion, two hundred forty-five million, three hundred fifty-one thousand, three hundred forty-three".