21043245351341 has 2 divisors, whose sum is σ = 21043245351342. Its totient is φ = 21043245351340.

The previous prime is 21043245351319. The next prime is 21043245351343. The reversal of 21043245351341 is 14315354234012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18511420200100 + 2531825151241 = 4302490^2 + 1591171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21043245351341 is a prime.

Together with 21043245351343, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21043245351295 and 21043245351304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21043245351343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10521622675670 + 10521622675671.

It is an arithmetic number, because the mean of its divisors is an integer number (10521622675671).

Almost surely, 2^{21043245351341} is an apocalyptic number.

It is an amenable number.

21043245351341 is a deficient number, since it is larger than the sum of its proper divisors (1).

21043245351341 is an equidigital number, since it uses as much as digits as its factorization.

21043245351341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 21043245351341 its reverse (14315354234012), we get a palindrome (35358599585353).

The spelling of 21043245351341 in words is "twenty-one trillion, forty-three billion, two hundred forty-five million, three hundred fifty-one thousand, three hundred forty-one".