Base | Representation |
---|---|
bin | 11110101101000101110… |
… | …111011011100110100111 |
3 | 21110201021121022202221012 |
4 | 132231011313123212213 |
5 | 234032240240214343 |
6 | 4253153210212435 |
7 | 305304536303051 |
oct | 36550567334647 |
9 | 7421247282835 |
10 | 2110001101223 |
11 | 7439346832a4 |
12 | 2a0b2312411b |
13 | 123c84058592 |
14 | 741a5c7c8d1 |
15 | 39d45241718 |
hex | 1eb45ddb9a7 |
2110001101223 has 2 divisors, whose sum is σ = 2110001101224. Its totient is φ = 2110001101222.
The previous prime is 2110001101163. The next prime is 2110001101237. The reversal of 2110001101223 is 3221011000112.
It is an a-pointer prime, because the next prime (2110001101237) can be obtained adding 2110001101223 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2110001101223 - 210 = 2110001100199 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 2110001101198 and 2110001101207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110001101283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055000550611 + 1055000550612.
It is an arithmetic number, because the mean of its divisors is an integer number (1055000550612).
Almost surely, 22110001101223 is an apocalyptic number.
2110001101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110001101223 is an equidigital number, since it uses as much as digits as its factorization.
2110001101223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2110001101223 its reverse (3221011000112), we get a palindrome (5331012101335).
The spelling of 2110001101223 in words is "two trillion, one hundred ten billion, one million, one hundred one thousand, two hundred twenty-three".
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