Base | Representation |
---|---|
bin | 101111111110011101001011… |
… | …001101101001111001110100 |
3 | 1000200002102012011111121111120 |
4 | 233332131023031221321310 |
5 | 210124011221234040200 |
6 | 2024432041141503540 |
7 | 62305153451413434 |
oct | 5776351315517164 |
9 | 1020072164447446 |
10 | 211000120221300 |
11 | 6125a715115303 |
12 | 1b7b92a1411bb0 |
13 | 90972c25867a7 |
14 | 3a166631322c4 |
15 | 195d8e60949a0 |
hex | bfe74b369e74 |
211000120221300 has 72 divisors (see below), whose sum is σ = 610573941974976. Its totient is φ = 56259301416960.
The previous prime is 211000120221227. The next prime is 211000120221311. The reversal of 211000120221300 is 3122021000112.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 211000120221300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 43947277 + ... + 48511476.
Almost surely, 2211000120221300 is an apocalyptic number.
211000120221300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211000120221300 is an abundant number, since it is smaller than the sum of its proper divisors (399573821753676).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211000120221300 is a wasteful number, since it uses less digits than its factorization.
211000120221300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92466377 (or 92466370 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 211000120221300 its reverse (3122021000112), we get a palindrome (214122141221412).
The spelling of 211000120221300 in words is "two hundred eleven trillion, one hundred twenty million, two hundred twenty-one thousand, three hundred".
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