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211010112000 = 293253379901
BaseRepresentation
bin1100010010000100101…
…1101100101000000000
3202011122122202022210100
43010201023230220000
511424122042041000
6240534155002400
721150012233622
oct3044113545000
9664578668710
10211010112000
1181541786316
1234a8aa39400
1316b8a37734c
14a2da464c12
15574ed5ea00
hex31212eca00

211010112000 has 480 divisors, whose sum is σ = 780638745744. Its totient is φ = 54743040000.

The previous prime is 211010111969. The next prime is 211010112007. The reversal of 211010112000 is 211010112.

It is a happy number.

It can be written as a sum of positive squares in 8 ways, for example, as 87455049984 + 123555062016 = 295728^2 + 351504^2 .

It is a tau number, because it is divible by the number of its divisors (480).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is not an unprimeable number, because it can be changed into a prime (211010112007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 21307050 + ... + 21316950.

Almost surely, 2211010112000 is an apocalyptic number.

211010112000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211010112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (390319372872).

211010112000 is an abundant number, since it is smaller than the sum of its proper divisors (569628633744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211010112000 is an equidigital number, since it uses as much as digits as its factorization.

211010112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9977 (or 9948 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 9.

Adding to 211010112000 its reverse (211010112), we get a palindrome (211221122112).

211010112000 divided by its reverse (211010112) gives a cube (1000 = 103).

The spelling of 211010112000 in words is "two hundred eleven billion, ten million, one hundred twelve thousand".