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2110322313133 is a prime number
BaseRepresentation
bin11110101101011001000…
…000110000011110101101
321110202002222202000211121
4132231121000300132231
5234033420003010013
64253245123020541
7305315516456656
oct36553100603655
97422088660747
102110322313133
11743a89a25591
122a0bb280a751
131240057722b8
14741d67b452d
1539d6354058d
hex1eb590307ad

2110322313133 has 2 divisors, whose sum is σ = 2110322313134. Its totient is φ = 2110322313132.

The previous prime is 2110322313131. The next prime is 2110322313163. The reversal of 2110322313133 is 3313132230112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1097606142889 + 1012716170244 = 1047667^2 + 1006338^2 .

It is a cyclic number.

It is not a de Polignac number, because 2110322313133 - 21 = 2110322313131 is a prime.

Together with 2110322313131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2110322313098 and 2110322313107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2110322313131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055161156566 + 1055161156567.

It is an arithmetic number, because the mean of its divisors is an integer number (1055161156567).

Almost surely, 22110322313133 is an apocalyptic number.

It is an amenable number.

2110322313133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110322313133 is an equidigital number, since it uses as much as digits as its factorization.

2110322313133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 2110322313133 its reverse (3313132230112), we get a palindrome (5423454543245).

The spelling of 2110322313133 in words is "two trillion, one hundred ten billion, three hundred twenty-two million, three hundred thirteen thousand, one hundred thirty-three".