Base | Representation |
---|---|
bin | 101111111111111101011001… |
… | …101000011010110001011101 |
3 | 1000200110021212210101220222221 |
4 | 233333331121220122301131 |
5 | 210132204321440131331 |
6 | 2024551325423505341 |
7 | 62315502033364354 |
oct | 5777753150326135 |
9 | 1020407783356887 |
10 | 211103441333341 |
11 | 6129a5151a4aa7 |
12 | 1b815317458251 |
13 | 90a3c7a15ab8b |
14 | 3a1b6652a699b |
15 | 1961441b52711 |
hex | bfff59a1ac5d |
211103441333341 has 2 divisors, whose sum is σ = 211103441333342. Its totient is φ = 211103441333340.
The previous prime is 211103441333339. The next prime is 211103441333357. The reversal of 211103441333341 is 143333144301112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 172640547525625 + 38462893807716 = 13139275^2 + 6201846^2 .
It is a cyclic number.
It is not a de Polignac number, because 211103441333341 - 21 = 211103441333339 is a prime.
Together with 211103441333339, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 211103441333297 and 211103441333306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211103441333371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105551720666670 + 105551720666671.
It is an arithmetic number, because the mean of its divisors is an integer number (105551720666671).
Almost surely, 2211103441333341 is an apocalyptic number.
It is an amenable number.
211103441333341 is a deficient number, since it is larger than the sum of its proper divisors (1).
211103441333341 is an equidigital number, since it uses as much as digits as its factorization.
211103441333341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 211103441333341 its reverse (143333144301112), we get a palindrome (354436585634453).
The spelling of 211103441333341 in words is "two hundred eleven trillion, one hundred three billion, four hundred forty-one million, three hundred thirty-three thousand, three hundred forty-one".
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