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211111220141 is a prime number
BaseRepresentation
bin1100010010011100110…
…1011001001110101101
3202011220201000011002022
43010213031121032231
511424323433021031
6240552210035525
721152350522553
oct3044715311655
9664821004068
10211111220141
1181593864368
1234ab8878ba5
1316ba52b8353
14a309a63bd3
155758b8297b
hex31273593ad

211111220141 has 2 divisors, whose sum is σ = 211111220142. Its totient is φ = 211111220140.

The previous prime is 211111220083. The next prime is 211111220143. The reversal of 211111220141 is 141022111112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207384606025 + 3726614116 = 455395^2 + 61046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211111220141 is a prime.

Together with 211111220143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211111220143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555610070 + 105555610071.

It is an arithmetic number, because the mean of its divisors is an integer number (105555610071).

Almost surely, 2211111220141 is an apocalyptic number.

It is an amenable number.

211111220141 is a deficient number, since it is larger than the sum of its proper divisors (1).

211111220141 is an equidigital number, since it uses as much as digits as its factorization.

211111220141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 211111220141 its reverse (141022111112), we get a palindrome (352133331253).

The spelling of 211111220141 in words is "two hundred eleven billion, one hundred eleven million, two hundred twenty thousand, one hundred forty-one".